Ice of mass 50g at 0°C was completely melted by 70% o...
Ice of mass 50g at 0°C was completely melted by 70% of the total heat energy supplied. Calculate the total heat energy supplied [Specific latent heat of fusion of ice = 336Jg−1]
2400J
6800J
7251J
24000J
Correct answer is D
The quantity of heat needed to melt ice = mL (where m is the mass of ice and L is the specific latent heat of fusion of ice)
Q = 50×336=16800J but this is 70% of the total heat supplied so that we have,
70% total heat = 16800J
70100 of total heat = 16800J
⇒ Total heat supplied = 16800×10070=24000J
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