The diagram shows a uniform meter rule AB which balances ...
The diagram shows a uniform meter rule AB which balances horizontally at the 90cm mark when a mass of 0.2kg is suspended from B. Calculate the mass of the meter rule.
0.05kg
0.20kg
0.80kg
1.00kg
Correct answer is A
Mr(90 - 50) = 0.2(100 - 90)
40Mr = 0.2 × 10
Mr | = | 2
40 |
= | 0.05kg |