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In the diagram, QR//ST, /PQ/ = /PR/ and < PST = 75o
In the diagram, QR//ST, /PQ/ = /PR/ and < PST = 75o. Find the value of y

In the diagram, QR//ST, /PQ/ = /PR/ and < PST = 75o. Find the value of y

A.

105o

B.

110o

C.

130o

D.

150o

View answer & explanation

Correct answer is A

In \(\bigtriangleup\) PQR,

Q = S = 75o (Corresponding angle)

R = Q = 75o (Base angles of an isosceles \(\bigtriangleup\))

But, y + 75o = 180o (Sum of angles in a straight line)

y = 180 - 75

y = 105o

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