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From the equation whose roots are x = $\frac{1}{2}$ and -\...

From the equation whose roots are x = $\frac{1}{2}$ and - $\frac{2}{3}$

A.

6x² - x + 2 = 0

B.

6x² - x - 2 = 0

C.

6x² + x + 2 = 0

D.

6x² + x - 2 = 0

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Correct answer is D

x = $\frac{1}{2}$ and x = $\frac{-2}{3}$

expand (x - $\frac{1}{2}$ )(x + $\frac{2}{3}$ ) = 0

x(x + $\frac{2}{3}$ ) - $\frac{1}{2}(x + \frac{2}{3}$ ) = 0

x² + $\frac{4x - 3x}{6} - \frac{2}{6} = 0$

$x^2 + \frac{x}{6} - 2 = 0$

6x² + x - 2 = 0

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