An electron of mass 9.1 x 10−31 kg moves with a sp...
An electron of mass 9.1 x 10−31 kg moves with a speed of 2.0 x 106 ms−1 round the nucleus of an atom in a Circular path of radius
6.1 x 1011 m. Calculate the centripetal force acting on the electron.
7.7 x 1047 N
6.0 x 10−8N
3.0 x 10−14N
1.3 x 10−26N
Correct answer is B
Centripetal force (Fr) = MV2r
i.e. Fr = Mv2r
= 9.1×10−31×2.0×106×2.0×1066.1×10−11 N
= (36.4×10−196.1×10−11) N
= 5.967 x 10−8 N
~ 6.0 x 10−8 N
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