A motorcycle starting from rest is uniformly accelerated ...
A motorcycle starting from rest is uniformly accelerated such that its velocity in 10s is 72kmhr−1. What is its acceleration?
108ms2
86ms2
4ms2
2ms2
Correct answer is D
where u = o m/s, t = 10s,
v = 72kmhr−1 ---> (72 X 1000) / 3600
: v = 20 m/s
Acceleration (a) = ( v - u ) / t ---> (20 - 0) / 10
: a = 2m/s2