The lengths of the minor and major arcs 54cm and 126cm re...
The lengths of the minor and major arcs 54cm and 126cm respectively. Calculate the angle of the major sector
360o
252o
246o
234o
Correct answer is B
Let 0 = angle of the minor sector
angle of the major sector = 360 - \(\theta\)(angle at a point)
2 \(\pi r\) = 54 + 126(i.e circumference of minor and major arc)
2\(\pi r = 180^o\)
r = \(\frac{180}{2\pi}\) = \(\frac{90}{\pi}\)
Lenght of ninor arc
= \(\frac{\theta}{360} \times 2 \pi r\)
54 = \(\frac{\theta}{360} \times 3 \pi r\)
\(\theta = \frac{360 \times 54}{2 \pi r}\)
but r = \(\frac{90}{\pi}\) substituting \(\frac{90}{\pi}\) for r
\(\theta = \frac{360 \times 54 \times \pi}{2 \times \pi \times 90}\)
\(\theta = 2 \times 54 = 108^o\)
angle of the major sector = 360 - 108o
= 252o
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