-12≤x < 3
-12<x≤3
-12<x<3
-12≤x≤3
Correct answer is C
2x2 - 5x - 3 = 0
2x2 - 6x + x - 3 = 0
2x(x - 3) + 1(x - 3) = 0
(2x + 1)(x - 3) = 0
2x + 1 = 0
2x = -1
x = -12
x - 3 = 0
-12 < x < 3
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