Subtract $\frac{1}{2}$ (a - b - c) from the sum of $\frac{1}{2}$ (a - b + c) and $\frac{1}{2}$
(a + b - c)

$\frac{1}{2}$ (a + b + c)

$\frac{1}{2}$ (a - b - c)

$\frac{1}{2}$ (a - b + c)

$\frac{1}{2}$ (a + b - c)

Correct answer is A

$\frac{1}{2}$ (a - b + c) + $\frac{1}{2}$ (a + b - c) - [ $\frac{1}{2}$ (a - b - c)]

$\frac{1}{2}a - \frac{1}{2}b + \frac{1}{2}c + \frac{1}{2}a + \frac{1}{2}b - \frac{1}{2}c - \frac{1}{2}a + \frac{1}{2}b + \frac{1}{2}c$

= $\frac{1}{2}a + \frac{1}{2}b + \frac{1}{2}c$

= $\frac{1}{2}(a + b + c)$

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