The diameter of a brass ring at 30 °C is 50.0 cm. To ...
The diameter of a brass ring at 30 °C is 50.0 cm. To what temperature must this ring be heated to increase its diameter to 50.29 cm? [ linear expansivity of brass = 1.9 x 10−5 K−1]
152.6 °C
182.6 °C
306.1 °C
335.5 °C
Correct answer is A
L1=50.
T1 = 30 + 273 = 303k
Linear expansivity = 1.9 x 10−5
L2 = 50.29
Temp rise= ?
L2 - L1 = 50.29 - 50 = 0.29
Linear expansivity = L2−L1L1(T2−T1)
1.9 x 10−5 = 0.2950∗(T2−303)
1.9 x 10−5 * 50 (T2 - 303) = 0.29
T2 = 0.2950∗1.9∗10−5 + 303
T2 = 152.6 °C
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