A car starts from rest and covers a distance of 40 m...
A car starts from rest and covers a distance of 40 m in 10 s. Calculate the magnitude of its acceleration
3.20 ms−2
0.25 ms−2
0.80 ms−2
4.00 ms−2
Correct answer is C
S = ut + 12at2
40 = 0 x 10 + 12a x 102
50a = 40
a = 4050
= 0.8m/s2
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