1
0
2
-1
Correct answer is A
Given: x+y=90°...(1)
(sinx+siny)2−2sinxsiny=sin2x+sin2y+2sinxsiny−2sinxsiny
= sin2x+sin2y...(2)
Recall: sinx=cos(90−x)...(a)
From (1), y=90−x...(b)
Putting (a) and (b) in (2), we have
sin2x+sin2y≡cos2(90−x)+sin2(90−x)
= 1
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