What quantity of heat is required to convert 20 g of ice at 0 ºC to water at the same temperature? (Specific latent heat of ice = 336 Jg\(^{-1}\))
A.
7.06 x 10\(^{3}\)J
B.
5.38 x 10\(^{3}\)J
C.
6.72 x 10\(^{3}\)J
D.
1.35 x 10\(^{3}\)J
Correct answer is C
quantity of heat = mass * Specific latent heat → 20 * 336
quantity of heat = 6720j or 6.72 x 10\(^{3}\)J
