2(x+1)2
2(x+1)(x+2
2(x+1)(x+2
2(x+1)(x+3
Correct answer is D
[1÷(x2+3x+2)]+[1÷(x2+5x+6)]
= 1÷(x2+3x+2)+[1÷(x2+5x+6)]
= [1÷((x2+x)+(2x+2))]+[1÷((x2+3x)+(2x+6))]
= [1 ÷ (x(x + 2) + 2(x +1))] + [1 ÷ (x(x + 3) +2(x + 3) )]
= [1 ÷ (x + 1)(x + 2)] + [1 ÷ ((x + 3) + (x + 2))]
=((x + 3) + (x + 1)) ÷ (x + 1)(x + 2)(x + 3)
Using the L.C.M
=((x + x + 3 + 1)) ÷ (x + 1)(x + 2)(x + 3)
=(2x+4)/(x+1)(x+2)(x+3) =2(x+2)/(x+1)(x+2)(x+3)
= 2(x+1)(x+3)