Find the tension in the two cords shown in the figure above. Neglect the mass of the cords, and assume that the angle is 38° and the mass m is 220 kg

[Take g = 9.8 ms-2]

Find the tension in the two cords shown in the figure above. Neglect the mass of the cords, and assume that the angle is 38° and the mass m is 220 kg

[Take g = 9.8 ms-2]

A.

\(T_1\) = 2864 N, \(T_2\)= 3612 N

B.

\(T_1\)= 3612 N, \(T_2\) = 2864 N

C.

\(T_1\)= 3502 N, \(T_2\)= 2760 N

D.

\(T_1\) = 2760 N, \(T_2\) = 3502 N

Correct answer is C

W =  mg  = 220 x 9.8 = 2156 N


⇒Sin 38º = \(\frac{2156}{T_1}\)

⇒ \(T_1\) =    \(\frac{2156}{Sin 38}\)

⇒ \(T_1\) =     3502 N

 

Cos 38º =  \(\frac{T_2}{T_1}\)

⇒ \(T_2\)  =   3502 x Cos 38º

⇒ \(T_2\) =   2760 N

 

;    \(T_1\) =   3502 N,  \(T_2\) = 2760 N.