A parallel plate capacitor separated by an air gap is mad...
A parallel plate capacitor separated by an air gap is made of 0.8m2 tin plates and 20 mm apart. It is connected to 120 V battery. What is the charge on each plate?
Take ε_o = 8.85×10^-12 Fm^-1
3.54nC
42.5nC
35.4nC
4.25nC
Correct answer is B
A= 0.8m^2 d= 20mm =\frac{20}{1000} = 0.02m
v =120v; ε_oA= 8.85 × 10^-12 fm^-1
C = \frac{ε_oA}{d}
C =\frac{8.85 × 10^-12×0.8}{0.02}
C= 3.54 × 10^-10 F
Q= CV
⇒ 3.54 × 10^-10 × 120 = 4.25×10^-8c
Q=42.5 × 10^-9c = 42.5nC