A beam of light travelling in water is incident on a glas...
A beam of light travelling in water is incident on a glass which is immersed in the water. The incident beam makes an angle of 40o with the normal. Calculate the angle of refraction in the glass.
[Refractive index of water = 1.33, Refractive index of glass = 1.5]
29.36o
25.37o
37.21o
34.75o
Correct answer is D
n1=1.33; n2=1.5; i=40°; r= ?
from snell's law:
n1 x sin i=n2x sin r
⇒1.33 x sin 40°=1.5 x sin r
⇒sin r = 0.5700
⇒r = sin−1 (0.5700)
⇒ r = 34.75