An electron moves from an energy level of -8.6 eV to anot...
An electron moves from an energy level of -8.6 eV to another level of -3.5 eV. Determine the frequency of the absorbed radiation. [1 eV = 1.6 × 1019 J, h = 6.6 × 1034 Js]
2.93×1015Hz
3.59×1016Hz
5.39×1015Hz
1.24×1015Hz
Correct answer is D
h = 6.6×10−34Js, 1eV = 1.6×10−19J, E1 = - 8.6eV, E2 = - 3.5eV, f = ?
ΔE = hf
f = \frac{ΔE}{h}
ΔE = E_2 - E_1 = - 3.5eV - (- 8.6eV) = 5.1eV
but 5.1eV = 5.1 X 1.6 \times 10^{-19} = 8.16 \times 10^{-19}J
f = \frac{8.16 \times 10^{-19}}{ 6.6 \times 10^{-34}}
Therefore, f = 1.24 \times 10^{15}Hz
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