2√1313
3√1313
4√1313
6√1313
Correct answer is C
tan x = 23(given), is illustrated in a right-angled Δ
thus m2 = 22 + 32
= 4 + 9 = 13
m = √13
Hence, 2sin x = 2 x 2m
2 x2√13
= 4√13
= 4√13=√13√13
= 4√1313
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