4x+5y−xy2xy
5y−4x+xy2xy
5x+4y−xy2xy
4x−5y+xy2xy
Correct answer is D
3x−yxy−2x+3y2xy+12
= 2(3x−y)−1(2x+3y)+xy2xy
= 6x−2y−2x−3y+xy2xy
= 4x−5y+xy2xy
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