$In the diagram, $\bar{PF}$, $\bar{QT}$, $\bar{RG}$ intersect at S and PG||RG. If < SPQ = 113o and < RSt = 220, find < PSQ$

In the diagram, $\bar{PF}$, $\bar{QT}$, $\bar{RG}$ intersect at S and PG||RG. If < SPQ = 113^o and < RSt = 220, find < PSQ

22^o

45^o

67^o

89^o

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Correct answer is B

In In the diagram given, $\alpha$ = 22^o (vertically opp. angles), $\alpha$ = $\beta$ (alternate angles)

< PSQ + 133^o + $\beta$ = 180^o (sum of angles of a $\Delta$)

< PSQ + 133^o + 22^o = 180^o

< PSQ = 180^o - (133 + 22)^o

45^o

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In the diagram, \(\bar{PF}\), \(\bar{QT}\), \(\bar{RG}\) intersect at S and PG||RG. If < SPQ = 113^o and < RSt = 220, find < PSQ

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In the diagram, \(\bar{PF}\), \(\bar{QT}\), \(\bar{RG}\) intersect at S and PG||RG. If < SPQ = 113o and < RSt = 220, find < PSQ

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In the diagram, \(\bar{PF}\), \(\bar{QT}\), \(\bar{RG}\) intersect at S and PG||RG. If < SPQ = 113^o and < RSt = 220, find < PSQ