If U = {x : x is an integer and 1 ≤ x ≤ 20 }
E1 = {x: x is a multiple of 3}
E2 = {x: x is a multiple of 4} and an integer is picked at random from U, find the probability that it is not in E2

$\frac{3}{4}$

$\frac{3}{10}$

$\frac{1}{4}$

$\frac{1}{20}$

Correct answer is A

U = {1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20}

E1 = {3, 6, 9, 12, 15, 18}

E2 = {4, 8, 12, 16, 20}

Probability of E2 = $\frac{5}{20}$ i.e $\frac{\text{Total number in}E_2}{\text{Entire number in set}}$

Probability of set E2 = 1 − $\frac{5}{20}$

= $\frac{15}{20}$

= $\frac{3}{4}$

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If U = {x : x is an integer and 1 ≤ x ≤ 20 }
E1 = {x: x is a multiple of 3}
E2 = {x: x is a multiple of 4} and an integer is picked at random from U, find the probability that it is not in E2

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If U = {x : x is an integer and 1 ≤ x ≤ 20 } E1 = {x: x is a multiple of 3} E2 = {x: x is a multiple of 4} and an integer is picked at random from U, find the probability that it is not in E2

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If U = {x : x is an integer and 1 ≤ x ≤ 20 }
E1 = {x: x is a multiple of 3}
E2 = {x: x is a multiple of 4} and an integer is picked at random from U, find the probability that it is not in E2