24oC
20oC
34oC
30oC
Correct answer is A
t ∝ h, t = 20, h t = ? h = 60 t = kh where k is constant 20 = 50k k = \(\frac{20}{50}\) k = \(\frac{2}{5}\) when h = 60, t = ? t = \(\frac{2}{5}\) × 60 t = 24oC
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