If a rod 10cm in length was measured as 10.5cm, calculate...
If a rod 10cm in length was measured as 10.5cm, calculate the percentage error
5%
5%
8%
7%
Correct answer is A
Actual measurement = 10cm
approximated value of measurement = 10.5cm
% error = \(\frac{\text{Actual measurement − Approximated}}{\text{Actual measure}}\) × 100
= \(\frac{10 − 10.5}{10}\) × 100
= \(\frac{-0.5}{10}\) × 100
ignore -sign i.e take absolute value
= \(\frac{0.5}{10}\) × 100
= 5 %
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