Find the equation of the locus of a point p (x, y) such t...
Find the equation of the locus of a point p (x, y) such that pv = pw, where v= (1, 1) and w = (3, 5)
2x + 2y = 9
2x + 3y = 8
2x + y = 9
x + 2y = 8
Correct answer is D
The locus of a point p(x, y) such that pv = pw where v = (1, 1)
and w = (3, 5). This means that the point p moves so that its distance from v and w are equidistance
√(x−x1)2+(y−y1)2 = √(x−x2)2+(y−y2)2
√(x−1)2+(y−1)2 = √(x−3)2+(y−5)2
square both sides
(x - 1)2 + (y - 1)2 = (x - 3)2 + (y - 5)2
x2 - 2x + 1 + y2 - 2y + 1 = x2 - 6x + 9 + y2 - 10y + 25
x2 + y2 -2x -2y + 2 = x2 + y2 - 6x - 10y + 34
Collecting like terms
x2 - x2 + y2 - y2 - 2x + 6x -2y + 10y = 34 - 2
4x + 8y = 32
Divide through by 4
x + 2y = 8
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