112
2
212
3
Correct answer is A
If x : y : z = 3 : 3 : 4, evaluate 9x+3y6x−2y
xy = 23 and yz = 34
Thus; x = 23T1 and z = 35T1
y = 37T2 and z = 47T2
Using y = y
35T1 = 37T2; T1T2 = 37 x 53
T1T2 = 1521
T1 = 15 and T2 = 21
Therefore;
x = 25 x 15 = 6
y = 35 x 15 = 9
y = 37 x 21 = 9 (again)
z = 47 x 21 = 12
Hence;
9x+3y6z−2y = 9(6)+3(9)6(12)−2(9)
54+2772−18 = 8154 = 32
= 112
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