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Find the 6th term of the sequence \(\frac{2}{3} \frac{7}{15}...

Find the 6th term of the sequence $\frac{2}{3} \frac{7}{15} \frac{4}{15}$ ,...

A.

- $\frac{1}{3}$

B.

- $\frac{1}{5}$

C.

- $\frac{1}{15}$

D.

$\frac{1}{9}$

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Correct answer is A

a = $\frac{2}{3}$ , d = $\frac{7}{15}$ - $\frac{2}{3}$

= 7 - 10

= $\frac{-3}{15}$

d = - $\frac{-1}{5}$

T6 = a + 5d

= $\frac{2}{3}$ + 5( $\frac{-1}{5}$

= $\frac{2}{3}$ - 1

= $\frac{2 - 3}{3}$

= $\frac{-1}{3}$

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