x = \(\frac{6 + 12}{d^2 + y}\)
x = \(\frac{12}{d^2 - y}\)
x = \(\frac{12}{y} - 2d^2\)
x = \(\frac{12}{2d^2 + y}\)
Correct answer is D
d = \(\sqrt{\frac{6}{x} - \frac{y}{2}}\)
\(d^2 = \frac{6}{x} - \frac{y}{2}\)
\(2xd^2 = 12 - xy\)
\(2xd^2 + xy = 12\)
x = \(\frac{12}{2d^2 + y}\)
In the figure, PT is tangent to the circle at U and QU/RS if TUR = 35º and SRU = 50º&...
Factorize completely: 6ax - 12by - 9ay + 8bx ...
Given that t = \(2 ^{-x}\), find \(2 ^{x + 1}\) in terms of t. ...
Find the area of the figure bounded by the given pair of curves y = x2 - x + 3 and y = 3...