In the diagram, NQ//TS, <RTS = 50\(^o\) and <PRT = 100\(^o\). Find the value of <NPR
110\(^o\)
130\(^o\)
140\(^o\)
150\(^o\)
Correct answer is B
< TSR = 180 - (80 + 50)
= 180 - (130)
= 50\(^o\)
< QPR = < TSR corresponding < s
< NPR + QPR = < NPR
180\(^o\) - < QPR = < NPR
180\(^o\) - 50 = < NPR
< NPR = 130\(^o\)
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