In the diagram, NQ//TS, <RTS = 50o and <PRT = 100...
In the diagram, NQ//TS, <RTS = 50o and <PRT = 100o. Find the value of <NPR
A.
110o
B.
130o
C.
140o
D.
150o
Correct answer is B
< TSR = 180 - (80 + 50)
= 180 - (130)
= 50o
< QPR = < TSR corresponding < s
< NPR + QPR = < NPR
180o - < QPR = < NPR
180o - 50 = < NPR
< NPR = 130o
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