12x−24x2
43x2−2x7x
4x2−27x+6
12x2−24x3−2x
Correct answer is D
ddx[log(4x3−2x)] ... (1)
Let u = 4x3 - 2x.
ddx(log(4x3−2x))=(ddu)(dudx)
ddu(logu) = 1u
dudx=12x2−2
∴
= \frac{12x^2 - 2}{4x^3 - 2x}
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