If P varies inversely as the square root of q, where p = ...
If P varies inversely as the square root of q, where p = 3 and q = 16, find the value of q when p = 4.
12
8
9
16
Correct answer is C
p∝1√q
⟹p=k√q
when p = 3, q = 16.
3=k√16
k=3×4=12
∴
when p = 4,
4 = \frac{12}{\sqrt{q}} \implies \sqrt{q} = \frac{12}{4}
\sqrt{q} = 3 \implies q = 3^2
q = 9
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