In the diagram above, O is the centre of the circle ...
In the diagram above, O is the centre of the circle ABC, < ABO = 26° and < BOC = 130°. Calculate < AOC.
26°
13°
80°
102°
Correct answer is D
< BAC = \(\frac{130}{2}\) (angle subtended at the centre)
< BAC = 65°
Also, x = 26° (theorem)
y = 65° - 26° = 39°
< AOC = 180° - (39° + 39°)
= 102°
Similar Questions
In the diagram, KL//MN, ∠LKP = 30o and ∠NMP = 45o. Find the size of the reflex ∠KPM....
A fair die is rolled once. What is the probability of obtaining 4 or 6? ...
If x : y = 5 : 12 and z = 52cm, find the perimeter of the triangle. ...
The first term of a G.P is 7. Find its 4th term, if its common ratio is 3. ...
Find a two-digit number such that three times the tens digit is 2 less than twice the units dig...
Cos x is negative and sin x is negative.Which of the following is true of x? ...