7y + 4x + 5 = 0
7y - 4x - 5 = 0
3y - 5x + 2 = 0
3y + 5x - 2 = 0
Correct answer is A
Equation: 4y = 7x + 3
⟹y=74x+34
Slope = coefficient of x = 74
Slope of perpendicular line = −174
= −47
The perpendicular line passes (-3, 1)
∴ Using the equation of line y = mx + b
m = slope and b = intercept.
y = \frac{-4}{7} x + b
To find the intercept, substitute y = 1 and x = -3 in the equation.
1 = \frac{-4}{7} (-3) + b
1 = \frac{12}{7} + b
b = \frac{-5}{7}
\therefore y = \frac{-4}{7} x - \frac{5}{7}
7y + 4x + 5 = 0
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