3x + 4y - 23 = 0
3x + 4y +23 = 0
3x - 4y +23 = 0
3x - 4y - 23 = 0
Correct answer is D
\(\frac{3}{4} = \frac{y + 5}{x - 1}\)
3(x - 1) = 4(y + 5)
3x - 3 = 4y + 20
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