In the diagram, O is the centre of the circle. If < NLM = 74\(^o\), < LMN = 39\(^o\) and < LOM = x, find the value of x.
134\(^o\)
126\(^o\)
113\(^o\)
106\(^o\)
Correct answer is A
L\(N\)M = 180\(^o\) - (74\(^o\) + 39\(^o\))
180\(^o\) - 113\(^o\)
= 67\(^o\)
L\(^O\)
M = x = 2 x 67\(^o\)
= 134\(^o\)
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