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In the diagram, O is the centre of the circle. If < NLM =...

$In the diagram, O is the centre of the circle. If < NLM = 74\(^o\), < LMN = 39\(^o\) and < LOM = x, find the value of x.$

In the diagram, O is the centre of the circle. If < NLM = 74 $^o$ , < LMN = 39 $^o$ and < LOM = x, find the value of x.

A.

134 $^o$

B.

126 $^o$

C.

113 $^o$

D.

106 $^o$

View answer & explanation

Correct answer is A

L $N$ M = 180 $^o$ - (74 $^o$ + 39 $^o$ )

180 $^o$ - 113 $^o$

= 67 $^o$

L $^O$

M = x = 2 x 67 $^o$

= 134 $^o$

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