Two numbers are removed at random from the numbers 1, 2, ...
Two numbers are removed at random from the numbers 1, 2, 3 and 4. What is the probability that the sum of the numbers removed is even?
23
12
13
14
Correct answer is B
12341(1,1)(1,2)(1,3)(1,4)2(2,1)(2,2)(2,3)(2,4)3(3,1)(3,2)(3,3)(3,4)4(4,1)(4,2)(4,3)(4,4)
sample space = 16
sum of nos. removed are (2), 3, (4), 5
3, (4), 5, (6)
(4), 5, (6), 7
(5), 6, 7, (8)
Even nos. = 8 of them
Pr(even sum) = 816
= 12
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