Given that sin x = 3/5, 0 ≤ x ≤ 90, evalu...
Given that sin x = 3/5, 0 ≤ x ≤ 90, evaluate (tanx + 2cosx)
21120
1120
2720
120
Correct answer is B
Sin x = opphyp
sinx = 35
using Pythagoras' theorem
hyp2 = opp2 + adj2
adj2 = 52 - 32 = 25 - 9
adj2 = 16
adj = √ 16
adj = 4.
tanx = oppadj
= 34
cosx = adjhyp
= 45
(tanx + 2cosx) = 34 + 2(45)
= 15+3220
= 4720 or
2 720
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