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make x the subject of the relation \(y = \frac{ax^3 - b}{3z}...

make x the subject of the relation y=ax3b3z

A.

x = 3ax3b3z

B.

x = 33yzba

C.

x = 33yz+ba

D.

x = 33yzba

Correct answer is C

y=ax3b3z

cross multiply

ax3b = 3yz

ax3 = 3yz + b 

divide both sides by a 

x3=3yz+ba

take cube root of both sides

therefore, x = 33yz+ba