12y2−y−6=0
12y2−y+6=0
12y2+y−6=0
y2+y−6=0
Correct answer is C
Let p = 23 and q = −34
using (y - p)(y - q) = 0
= ( y - 23)( y - (−34))=0
= (y−23)(y+34) = 0
y2+34y−23y−612=0
y2+112y−12 = 0
= multiply through by the l. c. m of 3 and 4 = 12
∴ the quadratic equation is 12y2+y−6=0
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