Find the mean deviation of a set of numbers: 14, 15, 16, 17, 18, and 19.
A.
2.5
B.
1.7
C.
1.5
D.
3.5
Correct answer is C
x̄ = \(\frac{ 14 + 15 + 16 +17 + 18 + 19}{6} = \frac{99}{6}\) = 16.5
M . D = \(\frac{ (14 - 16.5) + (15 - 16.5) + (16 - 16.5) + (17 - 16.5) + (18 - 16. 5) + (19 - 16.5) }{ 6}\)
M.D = \(\frac{(-2.5) + (-1.5) + (-0.5) + (0.5) + (1.5) + (2.5)}{6}\)
Taking the absolute value of the deviations
M.D = \(\frac{2.5 + 1.5 + 0.5 + 0.5 + 1.5 + 2.5}{6}\)
M.D = \(\frac{9}{6}\) = 1.5
