$C_{12}H_{22}O_{11(s)} + H_2SO_{4(aq)} → 12C(s) + 11H_2O(l) + H_2SO_{4(aq)}$
In the reaction above, tetraoxosulphate (VI) acid function as

A dehydrate agent

An oxidizing agent

A reducing agent

A catalyst

Correct answer is A

A dehydrating agent is a substance that dries or removes water from a substance.

so when sulphuric acid with sugar, the sugar is charred by the removal of water, $C_{12}H_{22}O_{11(s)} + H_2SO_{4(aq)} → 12C(s) + 11H_2O_{(l}) + H_2SO_{4(aq)}$

the sulphuric acid is serving as a dehydrating agent.

See all Chemistry questions & answers

See more JAMB questions & answers

$C_{12}H_{22}O_{11(s)} + H_2SO_{4(aq)} → 12C(s) + 11H_2O(l) + H_2SO_{4(aq)}$
In the reaction above, tetraoxosulphate (VI) acid function as

Similar Questions

Aptitude Tests

C12H22O11(s)+H2SO4(aq)→12C(s)+11H2O(l)+H2SO4(aq)C_{12}H_{22}O_{11(s)} + H_2SO_{4(aq)} → 12C(s) + 11H_2O(l) + H_2SO_{4(aq)} In the reaction above, tetraoxosulphate (VI) acid function as

Similar Questions

Aptitude Tests

$C_{12}H_{22}O_{11(s)} + H_2SO_{4(aq)} → 12C(s) + 11H_2O(l) + H_2SO_{4(aq)}$
In the reaction above, tetraoxosulphate (VI) acid function as