What mass of K₂CrO₄ is required to prepare 250cm³ of 0.020 mol dm³ solution?
[K₂CrO₄ = 194.2g mol^-1]

0.97g

9.70g

19.42g

97.10g

Correct answer is A

1 mole m^-3 K₂CrO₄ contains 194.2g mol^-1 in 1000cm³
1 mole m^-3 K₂CrO₄ contains 92.2g mol^-1 in 500cm³
1 mole m^-3 K₂CrO₄ contains 48.55g mol^-1 in 250cm³
If n molm^-3 K₂CrO₄ contain 48.55
0.02 molm^-3 will contain (0.02/1) * (48.55/1) = 0.97g

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