If a solution contains 4.9g of tetraoxosulphate (VI) acid...
If a solution contains 4.9g of tetraoxosulphate (VI) acid, calculate the amount of copper (II) oxide that will react with it
[Cu = 64, O = 16, S = 32, H = 1]
0.8g
4.0g
40.0g
80.0g
Correct answer is B
Equation of the reaction
H2SO4(g) + CuO(s) → Cu4(aq) + H2O
Relative molecular mass of H2SO4 = 1 + 2 + 32 + 16 + 4 = 98
Relative molecular mass of CuO = 64 + 16 =80
From the above equation, 98s of H2SO4 reacts with 80s of CuO.
∴ 4.9g of H2SO4 will react with
= (4.9 * 80)/98 of CuO = 392/98 = 4.0g
In which of the following processes is iron being oxidized? 1 Fe + H2SO4 → FeSO4 +H2 2 FeSO...
The three-dimensional shape of methane is ...
Which of the following compound is aromatic?...
A burning candle produces water and ...
What does X represent in the following equation? H 2(g) + 1/2O2(g) → H2O (l); ∆H = xKJ....
An electron can be added to a halogen atom to form a halide ion with ...
A common characteristic shared by iron and aluminium is that both? ...