In the electrolysis of CuSO4(g) using platinum electrodes...
In the electrolysis of CuSO4(g) using platinum electrodes, the reaction at the anode is
4H+ + 4e- → 2H2
4OH- + 4e- → 2H2O + O2
2OH - 2e- → 2OH
2OH- + 2OH- → 2H2O + O2
Correct answer is B
4OH<sup>-</sup> + 4e<sup>-</sup> → 2H<sub>2</sub>O + O<sub>2</sub> is the reaction of sun at the anode in the electrolysis of CuSO4 (g)
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