117.0g of sodium chloride was dissolved in 1.0dm3 of distilled water at 25°C. Determine the solubility in mol dm-3 of sodium chloride at that temperature
[Na = 23, Cl = 35.5]
1.0
2.0
3.0
4.0
Correct answer is B
Relative molecular mass of NaCl = 23 + 35.5 = 58.5 g/mol
No. of mole of NaCl = 117/58.5 = 2.0 mol