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$NH_{3(g)} + HCl_{(g)} → NH_4Cl_{(s)}$
The e...

$NH_{3(g)} + HCl_{(g)} → NH_4Cl_{(s)}$
The entropy change in the system above is

A.

positive

B.

zero

C.

negative

D.

indeterminate

View answer & explanation

Correct answer is C

$NH_{3(g)} + HCl_{(g)} → NH_4Cl_{(s)}$
Reactant = 2 moles of gaseous molecules
Product = 1 mole of gaseous molecule
Entropy change = 1 - 2 = -1 (negative)

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