CuO(s) + H\(_2\)(g) ↔ Cu(s) + H\(_2\)O(g)
What...
CuO(s) + H\(_2\)(g) ↔ Cu(s) + H\(_2\)O(g)
What is the effect of increasing the pressure on the equilibrium reaction above?
The equilibrium is shifted to the left
The equilibrium is shifted to the right
There is no effect
More H2(g) is produced
Correct answer is C
When amount / volume of gaseous reactants equal amount / volume of gaseous products, the change in pressure has no effect on the equilibrium position.