In a reaction: \(SnO_{2} + 2C → Sn + 2CO\) the mass of coke containing 80% carbon required to reduce 0.302 kg of pure tin oxide is?
(Sn - 119, O - 16, C - 12).

0.40 kg

0.20 kg

0.06 kg

0.04 kg

Correct answer is C

In the reaction: \(SnO_{2} + 2CO\)
From the equation above
2(12 g) carbon = 151 g \(SnO_{2}\)

24 g carbon =151 g \(SnO_{2}\)
= 0.302 kg \(SnO_{2}\) = 24/151g χ 0.0302 kg carbon = 0.048 kg carbon

Mass of coke is required not mass of carbon,so it is (0.048\(\times\)100)\(\div\)80 = 0.06

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In a reaction: \(SnO_{2} + 2C → Sn + 2CO\) the mass of coke containing 80% carbon required to reduce 0.302 kg of pure tin oxide is?
(Sn - 119, O - 16, C - 12).

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In a reaction: \(SnO_{2} + 2C → Sn + 2CO\) the mass of coke containing 80% carbon required to reduce 0.302 kg of pure tin oxide is? (Sn - 119, O - 16, C - 12).

Similar Questions

Aptitude Tests

In a reaction: \(SnO_{2} + 2C → Sn + 2CO\) the mass of coke containing 80% carbon required to reduce 0.302 kg of pure tin oxide is?
(Sn - 119, O - 16, C - 12).