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In a reaction: SnO2+2CSn+2CO the mass ...

In a reaction: SnO2+2CSn+2CO the mass of coke containing 80% carbon required to reduce 0.302 kg of pure tin oxide is?
(Sn - 119, O - 16, C - 12).

A.

0.40 kg

B.

0.20 kg

C.

0.06 kg

D.

0.04 kg

Correct answer is C

In the reaction: SnO2+2CO
From the equation above
2(12 g) carbon = 151 g SnO2

24 g carbon =151 g SnO2
= 0.302 kg SnO2 = 24/151g χ 0.0302 kg carbon = 0.048 kg carbon

Mass of coke is required not mass of carbon,so it is (0.048×100)÷80 = 0.06