10.0 dm³ of air containing H₂S as an impurity was passed through a solution of Pb(NO₃)₂ until all the H₂S had reacted. The precipitate of PbS was found to weigh 5.02 g. According to the equation:

Pb(NO₃)₂ + H₂S → PbS + 2HNO₃ the percentage by volume of hydrogen sulphide in the air is?



(Pb = 207, S = 32, GMV at s.t.p = 22.4dm³)

Similar Questions

What is the consequences of increasing pressure on the equilibrium reaction ZnO(s) + H2(g) Zn(s) + H...

The substance ZnO dissolves in sodium hydroxide solution and mineral acid solution to give soluble p...

The alkanol represented by the structure above is ...

At 25oC and 1atm, a gas occupies a volume of 1.50dm3. What volume will it occupy at 100oC and 1atm?...

How many grams of methylacetylene (propyne) CH3 — C Ξ CH will completely discharge the colour of ...

An iron nail placed in a solution copper (ll) tetraoxosulphate (VI) is soon covered with a deposit o...

An example of aromatic compound is? ...

Bauxite is the ore of ...

Millikan's contributions to the development of atomic theory is the determination of ...

Detergents have the general formula? ...