2.240 cm 3
22.40 cm 3
224.0 cm 3
2240 cm 3
Correct answer is B
Na2CO3 + 2HCC → 2NaII + H2O
1000 cm3 IM Na2CO3 contains 22400 cm3
10cm3 IM Na2CO3 will contain (10) / (100) x 224
=224 cm3
10 cm3 0.1 Na2CO3 will contain (o.1 x 224) / (1) = 22.4 cm3
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