What volume of CO₂ at s.t.p would be obtained by reacting trioxocarbonate (IV) with excess acid?

(G.M.V at s.t.p = 22.4 dm³)

2.240 cm ³

22.40 cm ³

224.0 cm ³

2240 cm ³

Correct answer is B

Na₂CO₃ + 2HCC → 2NaII + H₂O
1000 cm³ IM Na₂CO₃ contains 22400 cm³
10cm³ IM Na₂CO³ will contain (10) / (100) x 224
=224 cm³
10 cm³ 0.1 Na₂CO³ will contain (o.1 x 224) / (1) = 22.4 cm³

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What volume of CO₂ at s.t.p would be obtained by reacting trioxocarbonate (IV) with excess acid?

(G.M.V at s.t.p = 22.4 dm³)

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